Question #91488

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Answer 1 · 2017-10-20T13:06:05

#95"mm"#

To square root the distance, you must find the root of both the length and the units.

#sqrt(9025 "mm"^2)#
#=sqrt9025"mm"#
#95 "mm"#

Answer 2 · 2017-10-20T13:07:49

#(sqrt(9025))^2=9025#

Breaking the question down into its component parts:

The square root of #" "..................sqrt(?)#

9025mm #" "...............................sqrt(9025)#

squared #" "..............................(sqrt(9025))^2#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

This is the same as #sqrt(9025)xxsqrt(9025)#

Lets compare this to a known case:

Consider the value of 4

We know that #sqrt(4)=2#

So if we square 2 we get #2^2=4#

Thus #(sqrt(4))^2=4#

Using the above logic we have:

#(sqrt(9025))^2=9025#