Question

Question #95639

Answer 1

6m

Explanation:

When the Kinetic energy has reduced to half, the other part has become gravitational potential energy `E_w=mgh=(58,8 J)/2= 29,4 J`
hence `h=E_w/(mg) = (29,4J)/(0,5kg xx 9,8m/s^2)=6m`

Answer 2

`6"m"`

Explanation:

Initial Kinetic Energy `="KE"_i=58.8J`

Final Kinetic Energy `="KE"_f=58.8/2=29.4J`

Let's assume that the rest of Kinetic Energy has been converted into Gravitational potential energy.

Initial Gravitational potential Energy `="PE"_i=0J`

Final Gravitational potential Energy `="PE"_f=58.8-29.4=29.4J`

We need to know the height `color(blue)h`

So, `"PE"_f=mgcolor(blue)h`

`=>29.4J=0.5"kg"xx9.8m/s^2xxcolor(blue)h`

`=>color(blue)h=(29.4J)/(0.5"kg"xx9.8m/s^2)`

`=>color(blue)h=(29.4cancelN m)/(0.5cancel"kg"xx9.8cancel(m/s^2))`

`color(blue)h=6m`