Given that #3^(4-2x)# = #5^(3y+x)# and #3^(x-y)×25^(2y-1)#= 1. How to show #x^2-3y^2-6xy+4x+16y-8=0# ?
1 Answer
Oct 21, 2017
I tried this:
Explanation:
Have a look:
I tried this:
Have a look: