How do you evaluate the indefinite integral int (4x^5-6x^3+7x^2-8)dx?

1 Answer
Oct 22, 2017

(2x^6)/3 - (3x^4)/2 + (7x^3)/3 - 8x

Explanation:

int4x^5 dx = (4x^6)/6 = (2x^6)/3

int-6x^3 dx = (-6x^4)/4 = (-3x^4)/2

int7x^2 dx = 7x^3/3

int-8 dx = -8x

The above answer uses the formula:

intx^ndx = x^(n+1)/(n+1)

To obtain more reliable answers there are several online calculators available.

Hope my answer helped you.
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