What mass of carbon dioxide gas is present for a #52.0*mL# volume, at a temperature of #303*K#, and a pressure of #0.907*atm#?

1 Answer
Oct 22, 2017

#"Mass of carbon dioxide"~=80*mg#

Explanation:

From the Ideal Gas equation....

#n=(PV)/(RT)=(0.907*atmxx52.0*mLxx10^-3*L*mL^-1)/(0.0821*(L*atm)/(K*mol)xx303*K)#

#=1.90xx10^-3*mol#

And thus the mass of gas is given by.............

#"molar quantity"xx"molar mass"=1.90xx10^-3*molxx44.01*g*mol^-1=??g#