An object accelerates from rest to #5.9# #ms^-1# in #8.5# #s#. How far does it travel in this time?

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Answer 1 · 2017-10-23T02:52:43

It travels 25.1 m

Use this equation

#d=1/2(v+v_o)*t#

where #v_o# is the initial speed (zero in this case).

The equation is chosen because we do not know the acceleration of the car, and this equation does not require it.

#d = 1/2(5.9)*8.5 = 25.1 m#

Answer 2 · 2017-10-23T02:58:09

The distance traveled is #24.9# #m#.

First step is to find the acceleration:

#v=u+at#

Rearrange to make #a# the subject:

#a=(v-u)/t=(5.9-0)/8.5=0.69# #ms^-2#

Then:

#s=ut+1/2at^2=0xx8.5+1/2xx0.69xx8.5^2=24.9# #m#