How do you solve #18t-6t=24#?

3 Answers
Oct 24, 2017

#t =2#. Check out the explanation :)

Explanation:

The expression is able to solve by puttin t on evidence on the left side of the equation:

# t * (18 - 6) = 24#
# t*(12) = 24#
#12t = 24#

12 is now multiplying #t#, and goes to the other side of the equation dividing:

# 12t = 24 => t = 24/12 = 2#

Oct 24, 2017

#t=2#

Explanation:

#18t-6t=12t# because they are both like terms, thus they can be subtracted from each other.

So, #12t=24#, and now if we divide both sides by 12 we will isolate #t# to determine what #t# is.

#t=2#

Oct 24, 2017

The terms on the LHS are both variables, so they can be subtracted easily
#12t=24#
Now, transfer 12 to RHS
#t=24/12#
Notice that as 12 was in multiplication in LHS (12 x t), it is in division in RHS.
#t=(cancel(24)2)/(cancel(12)1)#
So,
#t=2#