Question

Question #1be4d

Answer 1

a = 2.30 m/s²
v = 23.0 m/s

Explanation:

Part C

Distance travelled by motorcycle 1 in 10 seconds
= Speed × Time `= 6.50 ms^-1 × 10 s = 65.0 m`

So, at t = 0 Motorcycle 1 is at x = 65.0 m + 50 m = 115 m

After 10 seconds both are at x = 115 m

For motorcycle 2

`S = ut + 1/2at^2`

`115 m = 0 + 1/2a(10.0 s)^2`

`a = [(2 × 115) / (10.0)^2] ms^-2 = 2.30 ms^-2`

Acceleration of motorcycle 2 is 2.30 m/s²

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Part D

`v = u + at = 0 + (2.30 ms^-2 × 10 s) = 23.0 ms^-1`

Speed of motorcycle 2 when it passes motorcycle 1 is 23.0 m/s