Question #1be4d

1 Answer
Oct 27, 2017

a = 2.30 m/s²
v = 23.0 m/s

Explanation:

Part C

Distance travelled by motorcycle 1 in 10 seconds
= Speed × Time #= 6.50 ms^-1 × 10 s = 65.0 m#

So, at t = 0 Motorcycle 1 is at x = 65.0 m + 50 m = 115 m

After 10 seconds both are at x = 115 m

For motorcycle 2

#S = ut + 1/2at^2#

#115 m = 0 + 1/2a(10.0 s)^2#

#a = [(2 × 115) / (10.0)^2] ms^-2 = 2.30 ms^-2#

Acceleration of motorcycle 2 is 2.30 m/s²


Part D

#v = u + at = 0 + (2.30 ms^-2 × 10 s) = 23.0 ms^-1#

Speed of motorcycle 2 when it passes motorcycle 1 is 23.0 m/s