Question #ef9c4

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kceylan
Oct 27, 2017

20 gram of %50 glucose solution

Explanation:

assumng that the density of the solutions are 1 gr/ml
1 liter of 10% soltion is 1000 gram and includes 10 gram of glucose and 990 grams of water. So we need 10 grams of glucose
Then we need 20 grams of %50 solution which contains 10 gr of glucose and 10 grams of water. Therefore take 20 gr of 50% glucose soltion add 1000-20=980 gr of pure water on it, you will get 1kg of 10% solution.

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