How do you solve #4( 9b + 11) - 13b = 19b#?

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Answer 1 · 2017-10-27T14:25:15

#b = - 11#

#4(9b + 11) - 13b = 19b#

Expanding the bracket!

#36b + 44 - 13b = 19b#

#36b - 13b + 44 = 19b#

#23b + 44 = 19b#

#23b + 44 - 19b = 0#

#23b - 19b + 44 = 0#

#4b + 44 = 0#

Rearrange the equation!

#4b = - 44#

Divide both sides by #4#

#(4b)/4 = - 44/4#

#(cancel4b)/cancel4 = - 44/4#

#b = - 44/4#

#b = - 11#