Question

Question #ccd24

Answer 1

`5.77 × 10^-19 "Joules"`

Explanation:

`E = (hc) / λ = (6.626 × 10^-34 "Js" × 3 × 10^8 "ms"^-1) / (3.44 × 10^2 cancel"nm" × 10^-9 "m"/cancel"nm") = 5.77 × 10^-19 "Joules"`