Question

Question #7903f

Answer 1

`y=-2/3x-2`

Explanation:

If it is parallel the gradients will be the same for both lines.
To find the gradient of the equation given it needs to be rearranged in to the form:

`y=mx+c`

this gives us:

`3y=3-2x` then divide by 3 to cancel `3y` to `y`
`=y=-2/3x+1`

gradient = `m`, therefore gradient is equal to `-2/3`

now we know the gradient and a point on the line we can substitute these values in the `y=mx+c` to find the value of `c`

this gives us:
`-4=-2/3(3)=c`

when solved for `c` we get `c=-2`

with the gradient value and the value of `c` the equation is:
`y=-2/3x-2`