Question

Question #02e27

Answer 1

`q=12.329kJ`

Explanation:

We are going to use the equation `q=mc∆T` where q is the energy, m is the mass of all liquid, c is the specific heat capacity and ∆T is the change in temperature.

To calculate ∆T you do final temperature minus initial temperature:

`∆T = 87-2 -> ∆T = 85˚C`

Specific heat capacity of water is `4.18 J Kg^-1 K^-1`

Total mass of liquid is 34.7g

Now plug these values into the equation to find `q`:

`q= 34.7*4.18*85 -> q= 12329J`

To have it in kJ divide it by a 1000:

`12329/1000 =12.329kJ`