Question

How do you solve and graph `abs(x+1)<0`?

Answer 1

No solutions
graph{abs(x+1) [-10, 10, -5, 5]}

Explanation:

We can note that `|a| >= 0, |a|` is never negative for all real `a`, so hence `|x+1|` is never negative, hence no solutions to `|x+1|<0`.

To sketch this graph, we can consider `y = x+1`
graph{y = x+1 [-10, 10, -5, 5]}

Then as we know `|a| >= 0` for all real a, we just take the graph in the domain where the function is negative, and reflect in the x axis, so for `x<-1` we make possitive, yielding;

graph{|x+1| [-10, 10, -5, 5]}

We can see clearly from this that `|x+1|` is never negative