Question #8a660

1 Answer
Oct 29, 2017

#x= 12.2 +root2 7 i#
#x= 12.2 -root2 7 i#

Explanation:

#-2root2 (x-12.2) -4 = 10#

Hence;
#root2 (x-12.2) +2 = -5#
#root 2 (x-12.2) = -7 #

Hence;
#x-12.2 = root2 (-7) #
Note #root2 (-7) = root2 (-1) * root2 7#
Hence # x-12.2 = root2 7 *i#

#x= 12.2 +root2 7 i#
#x= 12.2 -root2 7 i#