How do you solve #2( 6+ 4b ) + 3b = 7b - 4( b - 3)#?

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Answer 1 · 2017-10-30T02:12:28

#therefore b=0#

#2( 6+ 4b ) + 3b = 7b - 4( b - 3)#

Use distributive property #a(b+c)=ab+ac# to open the brackets:

#=> 12+8b + 3b = 7b - 4b+ 12#

Take all terms with variable #b# on left hand side and rest of the terms on right hand side of the equation applying rules of transposition:

#=> 8b + 3b + 4b - 7b = +12-12#

#=> 8b = 0#

#therefore b=0#