The zeros are -3, -1, and 4. #p(-2) = 24#. What is the function #p(x)#?

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Answer 1 · 2017-10-30T05:01:03

#p(x)=4x^3-52x-48#

As the zeros are #-3, -1# and #4#, the#p(x)# can be written as

#p(x)=a(x+3)(x+1)(x-4)#

and as #p(-2)=24#, we have

#a(-2+3)(-2+1)(-2-4)=24#

or #axx1xx(-1)xx(-6)=24#

or #6a=24# i.e. #a=4#

and we have #p(x)=4(x+3)(x+1)(x-4)#

= #4(x^3-13x-12)#

= #4x^3-52x-48#