Question #8f437

1 Answer
Oct 30, 2017

31.5

Explanation:

consecutive integers means that they're one after the other (eg 1,2,3,4).

So your first integer is #a#, the next (b) is #a+1#, then c: #a+2#, then d: #a+3#.
We are to find the sum of the last two integers, that is, #c+d#. Or #(a+2)+(a+3)#. Let's call it #x#.

And we know that the sum of them (all added up) = 59

So #a + (a+1)+(a+2)+(a+3)=59#
Expand all the brackets and simplify: #4a + 6=59#

Now solve for #a#:
#4a=53#
#a=13.25#

Therefore the integers are 13.25, 14.25, 15.25, and 16.25. These add up to 59 which fits the criteria.

So the sum of the last two is #15.25+16.25=31.5#