Question #a2118

1 Answer
Oct 30, 2017

See the answer below...

Explanation:

ACCELERATION:- change of velocity in a certain time...

If initial and final velocity are #color(red)(u# and #color(red)(v# respectively by time #color(red)(t# then the acceleration #(v-u)/t#unit.

Here acceleration is #color(darkred)((48.2-18.2)/2.45=12.25ms^-2#

Another formula to determine the distance(S) traveled is
#color(red)((v^2-u^2)/(2a)=s# where a is acceleration...

The distance is #color(red)((48.2^2-18.2^2)/(2xx12.25)=81.34m#

Hope it helps...
Please response after checking it...
Thank you...