Question #f6828

1 Answer
Oct 30, 2017

#"CHCl"#

Explanation:

#1.# Convert percentages into moles assuming that 100g of that substance is present

#color(red)(C=24.77%=24.77g )" (in 100g of that substance)"#

#color(red)(=(24.77g)/(12g/"mol")=2.064color(white)i"mol"#

#color(blue)(Cl=75.15%=75.15g#

#color(blue)(=(75.15g)/(35.5g/"mol")=2.117color(white)i"mol"#

#color(green)(H=2.08%=2.08g#

#color(green)(=(2.08g)/(1g/"mol")=2.08color(white)i"mol"#

#2.# Divide by the lowest number

# C->color(red)(2.064/2.064~~1#

#H-> color(blue)(2.117/2.064~~1#

#Cl->color(green)(2.08/2.064=1#

#3.# Write the empirical formula
#color(red)( C_1)color(blue)( H_1)color(green)( Cl_1)#

#color(red)( C)color(blue)( H)color(green)( Cl)-># webq.org