How do you evaluate #(5x + 4y ) ( x + 2y )#?

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Answer 1 · 2017-10-31T21:44:09

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(5x) + color(red)(4y))(color(blue)(x) + color(blue)(2y))# becomes:

#(color(red)(5x) xx color(blue)(x)) + (color(red)(5x) xx color(blue)(2y)) + (color(red)(4y) xx color(blue)(x)) + (color(red)(4y) xx color(blue)(2y))#

#5x^2 + 10xy + 4xy + 8y^2#

We can now combine like terms:

#5x^2 + (10 + 4)xy + 8y^2#

#5x^2 + 14xy + 8y^2#