Question

0.5 g of a base was completely neutralised by 100 ml of 0.2 N acid. equivalent weight of the base is??

Answer 1

25 g/eq

Explanation:

`"Equivalents of acid = Normality of acid × Volume of acid in litres"`

`= 0.2 N × 100 cancel(ml) × 10^-3 l/cancel(ml) = 0.02 color(white)x"equivalents"`

For complete neutralisation
Equivalents of acid = Equivalents of base

`"Equivalent weight" = "Weight" / "Equivalents" = (0.5 g) / (0.02 color(white)"o""equivalents") = 25` gram/equivalent