If #pH=8#, what are #[H_3O^+]# and #[HO^-]#?

Question

1024 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-02T07:43:33

0.00000001

The conversion from pH to [H+] is: #10^-pH#

Therefore, you can just do the math having that formula and the pH value: #10^-8 = 1 E-8 or 0.00000001#

Keep in mind that some professors/textbooks will use [H3O+] instead of [H+], but they are both referring to the same thing.

Hope this helped (c:

Answer 2 · 2017-11-02T08:39:18

#[H_3O^+]=10^-8*mol*L^-1#

By definition, #pH=-log_10[H_3O^+]#....(note that we use #H^+# and #H_3O^+# interchangeably). And thus if #pH=8#, #[H_3O^+]=10^(-8)*mol*L^-1#.

Note that in aqueous solution,...

#pH+pOH=14#...and so....

....... since #[HO^-]=10^(-6)*mol*L^-1#.....this solution is ALKALINE given that there are more hydroxide ions than hydronium ions....