Question

The region is bounded by the given curves `y=0, y=sqrt(4-x^2), 0<=x<=1` is roated about the x-axis, how do you find the volume of the two solids of revolution?

Answer 1

There aren't two solids, only one.

Explanation:

`V = int_0^1 pi(sqrt(4-x^2))^2 dx = piint_0^1(4-x^2) dx = (11pi)/3`