How do you solve #5=(u+6)/5 + (5u-2)/6#?

1 Answer
Nov 2, 2017

u=4

Explanation:

First, since there are fractions in this question, we can find the common denominator and group the fractions together, which is easier for us to do the question.

#5=(u+6)/5+(5u-2)/6#
#5=[(u+6)*6]/(5*6)+[(5u-2)*5]/(6*5)#
#5=(u*6+6*6)/30+(5u*5-2*5)/30#
#5=(6u+36+25u-10)/30#

Then, we can multiply by 30 on both sides to eliminate the denominator.

#5*30=(6u+36+25u-10)/30*30#
#150=26+31u#
#124=31u#
#u=124/31=4#

Here is the answer. Hope this can help you :)