Question #a9c10

1 Answer
Junaid Mirza
Nov 3, 2017

7.250 kilo calories

Explanation:

Heat required to raise the temperature of ice from -10°C to 0°C #=Q_1#
Heat required to convert ice at 0°C to water at 0°C #=mL_("fusion")#
Heat required to raise temperature of water at 0°C to 100°C #=Q_2#
Heat required to convert water at 100°C to steam at 100°C #=mL_(vapour)#

Total heat required #=Q_1 + mL_(fusion) + Q_2 + mL_(vapour)#

#=mS_(ice)dT + mL_(fusion) + mS_(water)dT’ + mL_(vapour)#

#= (10g × (0.5 cal)/(g°C) xx (0 - (-10)°C)) + (10g × (80 cal)/(g)) + (10g × (1 cal)/(g°C) × (100 - 0)°C) + (10g × (540 cal)/(g°C))#

#= 50 cal + 800 cal + 1000 cal + 5400 cal#

#= 7250 cal#

#= 7.25 kcal#

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