Question

Question #8c624

Answer 1

`1.05*10^-2` mol/L.

Explanation:

Fluoride ions containted in 1 L(=1000 g) of the solution is:
`1000 (g) * (200("ppm")) /(10^6) =0.200 (g)`.

The molar mass of fluorine atom is 19.00.
Thus, the molar concentration is
`(0.200(g/L))/(19.00(g/(mol)))=1.05*10^-2 ((mol)/L)`.