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Answer 1 · 2017-11-03T04:52:55

#1/(9*x^4)#

or

#1/9*x^-4#

#(3x^2)^(-2)#

#=1/(3x^2)^(2)#

#=1/(3^2*(x^2)^2)#

#=1/(9*x^4)#

#=1/9*x^-4#

Answer 2 · 2017-11-03T05:15:38

#1/(9x^4)#

#color(blue)((3x^2)^(-2)#

Remember,

#color(brown)((x)^-y=1/(x)^y#

So,

#rarr1/(3x^2)^2#

Now,

#color(brown)((xy)^z=x^zy^z#

So,

#rarr1/(3^2x^(2(2)))#

#color(green)(rArr1/(9x^4)#

Hope this helps!!! ☺☻