How do you solve #2y-(5y+1)=1#?

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Answer 1 · 2017-11-03T09:35:02

By arranging the equation.

Your equation

#2y - 5y - 1 = 1#

When you rewrite down after combining y and numbers:

#-3y = 1+1#

#-3 y = 2#

#y= -2/3#

Answer 2 · 2017-11-03T09:35:36

the solution is #y=-2/3#

the given equation is #2y-(5y+1)=1# #rArr2y-5y-1=1#
#rArr-3y=2# #rArry=-2/3#