Question #04c24

1 Answer
P dilip_k
Nov 5, 2017

#LHS=tan(θ/2) + cot(θ/2)#

#=tan(θ/2) + 1/tan(θ/2) #

#=(tan^2(θ/2) + 1)/tan(θ/2) #

#=(2(1+tan^2(θ/2) ))/(2tan(θ/2)) #

#=2/((2tan(theta/2))/(1+tan^2(θ/2) )) #

#=2/(sin(2*1/2*theta))#

# = 2cscθ=RHS#

Formula used

#(2tan(x))/(1+tan^2(x))=sin2x#

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