Given a right triangle triangle ABC with C=90^circ, if a=2, c=6, how do you find b?

3 Answers
Nov 5, 2017

b= 4sqrt(2)

Explanation:

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Using the Pythagorean Theorem,
a^2 + b^2 = c^2
b = sqrt(c^2 - a^2)
b = sqrt(6^2 - 2^2)
b= 4sqrt(2)

Nov 5, 2017

The side b is 4sqrt2 unit.

Explanation:

in right triangle Delta ABC , /_C=90^0 , a=2 , c=6 ; c is

the side opposite to the right angle, so it is hypotenuse,

a and b are the adjacent sides of the right angle .

We know in right triangle Delta ABC, a^2+b^2=c^2

:. 2^2+b^2=6^2 or b^2= 36-4 =32 :. b =sqrt32 or b=4sqrt2

unit. The side b is 4sqrt2 unit [Ans]

Nov 5, 2017

4sqrt2

Explanation:

Consider the diagram

paintpaint

Since this is a right triangle,

We can find the length b by using the Pythagoras theorem

color(blue)(a^2+b^2=c^2

Plugin the values

rarr2^2+b^2=6^2

rarr4+b^2=36

rarrb^2=32

Take the square root of both sides

rarrsqrt(b^2)=sqrt(32)

rarrb=sqrt(16*2)

color(green)(rArrb=4sqrt2

Hope that helps!!! ☺♣☻