Question #fe5a3

1 Answer
Nov 5, 2017

sec2(x2)=(csc2x)(22cosx)

Explanation:

sec2(x2) = 1cos2(x2)

Half angle identity forumla = cos2(a2)=1+cos(a)2

11+cos(a)/2= 21+cos(x)

Then multiply both numerator and denominator by 1-cos(x)

Resulting to

22cos(x)1cos2(x)

Then with the identity

sin2=1cos2

The final result will be

22cos(x)sin2(x) = (22cos(x))csc2(x)