Question #17573

1 Answer
Nov 5, 2017

878.0254mL

Explanation:

Given:
P_1=1.05atm*(760mmHg)/(1atm)=798mmHg
V_1=770mL
T_1=37^oC=310.15K
P_2=675mmHg
T_2=26^oC=299.15K
V_2=?

Using the combined gas law,
(P_1V_1)/T_1=(P_2V_2)/T_2

Rearranging the equation,
V_2=(P_1V_1T_2)/(T_1P_2)

Substituting the given values,
V_2=(798*770*299.15)/(310.15*675)
V_2=878.0254mL