How do you solve #5(3y-9) + 4 = 18 - 6(5 -2y)#?

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Answer 1 · 2017-11-06T13:30:22

#y = 29/3#

First, you have to expand the equation.
#15y-45+4=18-30+12y#

Simplify:
#15y-41=12y-12#

Bring #y# to one side and the constants to the other:
#15y-12y=41-12#

Simplify:
#3y=29#

Divide both sides by #3#:
#y=29/3#

Answer 2 · 2017-11-06T16:04:12

#y=29/3#

#5(3y -9)+4=18-6(5-2y)#

Let's start by using the distributive property

#(5)(3y)+(5)(-9)+4=18 +(-6)(5)+(-6)(-2y)#

#15y-45 +4 =18-30+12y#

#15y - 41 = 12y - 12#

Then subtract #12y# from both sides

#15y -41 -12y =cancel(12y) -12cancel(-12y)#

#3y -41 =-12#

Add #41# to both sides

#3y -41+41 = -12+41#

#3y =29#

#y=29/3#