Question #291b1

1 Answer
Nov 6, 2017

Below

Explanation:

Let theta= x

(1/sin(x)-cos(x)/sin(x))(1sin(x)cos(x)sin(x))

=((1-cos(x))/sin(x))(1cos(x)sin(x))

Square both numerator and denominator

=(((1-cos(x))^2)/sin(x)^2)((1cos(x))2sin(x)2)

Convert sin^2(x)sin2(x) to its identity and split the numerator

=((1-cos(x))(1-cos(x)))/(1-cos^2(x))(1cos(x))(1cos(x))1cos2(x)

Split the denominator by using diff. of two squares

=((1-cos(x))(1-cos(x)))/((1-cos(x))(1+cos(x))(1cos(x))(1cos(x))(1cos(x))(1+cos(x))

Cancel terms

=(cancel(1-cos(x))(1-cos(x)))/(cancel(1-cos(x))(1+cos(x))

End.