How do you solve the following system of equations?: #-x- 6y = 2 , 4x+y=8#?

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Answer 1 · 2017-11-06T22:37:05

#y=-16/23#

#x=50/23#

#-x-6y=2#
#4x+y=8#

Make #y# the subject in the second equation:

#y=8-4x#

Then inject that as #y# in the first equation:

#-x-6(8-4x)=2#

Expand and solve for #x#

#-x-48+24x = 2 -> 23x=50#

#x=50/23#

Place that #x# value into the rearranged equation to find #y#

#y=8-200/23#

#y=184/23 - 200/23#

#y=-16/23#