How do you multiply #(3x ^ { 2/ 5} - 3y ^ { 1/ 2} ) ( 6x ^ { 2/ 5} - 4y ^ { 1/ 2} )#?

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Answer 1 · 2017-11-07T02:50:18

#18x^(4/5)*-30x^(2/5)4y^(1/2)*12y#

You can use th FOIL method.

#(3x^(2/5)-3y^(1/2))(6x^(2/5)-4y^(1/2))#

F: #3x^(2/5) * 6x^(2/5)=18x^(4/5)#

O: #3x^(2/5)*-4y^(1/2)=-12x^(2/5)4y^(1/2)#

I: #-3y^(1/2)*6x^(2/5)=-18x^(2/5)y^(1/2)#

L: #-3y^(1/2)*-4y^(1/2)=12y#

Combining like terms, the final answer will be:

#18x^(4/5)*-30x^(2/5)4y^(1/2)*12y#