How do you solve #2( 4y - 3) - 7= y - 5#?

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Answer 1 · 2017-11-07T20:10:23

#y = 8/7 = 1.143#

#2(4y - 3) - 7 = y - 5#

Firstly you want to start by expanding the brackets:

#8y - 6 - 7 = y - 5#

Then tidy the equation up:

#8y - 13 = y - 5#

Then you want to bring the like terms together:

#8y = y + 8#

#7y = 8#

Then divide by #7# to get #y# on its own:

#y = 8/7#

#8/7 = 1.143 = y#