How do you solve $4x +8 <= 6x -20$ ?

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Answer 1 · 2017-11-08T08:42:09

$x >=14$

Pretend that your $<=$ here is just a plain old $=$ . Balance it like you always would :)

$4x+8<=6x-20$ Subtract $6x$ from both sides

$-2x+8<=-20$ Subtract $8$ from both sides

$-2x<=-28$ Divide both sides by $-2$ and do not forget to flip the sign because you're dividing by a negative number!

$x >= 14$

How do you solve 4x +8 <= 6x -204x +8 <= 6x -20?