What is the equation of the line that has a slope of #4/7# and passes through (1, 3)?

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Answer 1 · 2017-11-09T03:10:31

#y = 4/7x + 17/7#

Slope (m) #=4/7#

#(x,y) = (1,3)#

#x = 1#

#y = 3#

#y = mx + c#

#3 = (4/7xx1) + c#

#c = 3 - 4/7#

#c = (3 × 7/7) - 4/7#

#c = 21/7 - 4/7#

#c = (21 - 4)/7#

#c = 17/7#

∴ #"Equation of line is"# #y= 4/7x + 17/7#

Answer 2 · 2017-11-09T03:13:54

#y = (4/7)x + (17/7)#

Format of equation with slope and coordinates of one point is
#(y-y_1) = m (x-x_1#

Given #x_1=1, y_1=3# & #m=4/7#

#y - 3 = (4/7) (x- 1)#

#7y-21 = 4x-4#

#7y = 4x + 17#

#y = (4/7)x + (17/7)#