Question #b0b36

1 Answer
Mark C.
Nov 9, 2017

The additional info in the question is confusing, but let’s make the assumption that acceleration is constant, otherwise it’s very tricky!

Explanation:

We use one of the kinematic equations, #v^2 = u^2 + 2a.s# and, because we know that the initial velocity, u is zero, it simplifies to #v^2 = 2a.s# so #a = v^2/(2s#

#a = 559^2/[2xx0.803)#

#a = 194570.9 m/s^2# as you are given 3 s.f. in the question we leave it as 3 s.f. so #a = 1.94xx10^5 ms^-2#

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