What is the weight of an anhydrous solvent required to make a certain volume of solution ?

Question

a) what weight of anhydrous copper (II) sulphate would be required to make one litre of a solution containing 10.0g of Cu2+ ions per litre ?

b) what weight of copper (II) sulphate pentahydrate would be required to make the solution in part (a) above?

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Answer 1 · 2017-11-09T21:39:54

#a.# approx. #25*g#

#"Moles of cupric ion"# #=# #(10*g)/(63.55*g*mol^-1)=0.157*mol.#

And thus #[CuSO_4](aq)-=0.157*mol*L^-1#

And in a one litre volume there is a mass of....

#0.157*mol*L^-1xxunderbrace(159.61*g*mol^-1)_"molar mass of copper sulfate"=25.12*g# WITH RESPECT to #CuSO_4#.

#b.# if we started with the pentahydrate we would take the product...

#0.157*mol*L^-1xxunderbrace(249.69*g*mol^-1)_"molar mass of copper sulfate pentahydrate"=39.20*g# WITH RESPECT to #CuSO_4*5H_2O#.