Question

What is the domain and range of `f(t) = root3(3) sqrt (6t − 2)`?

Answer 1

Domain: `t>=1/3 or [1/3 ,oo)`
Range : `f(t) >=0 or [0,oo)`

Explanation:

`f(t) = root(3) 3 sqrt (6t-2)` Domain: Under root `>=0` otherwise

`f(t)` will be undefined. `:. 6t-2 >=0 or t>=1/3`.

Domain: `t>=1/3 or [1/3 ,oo)` . Range will not be any negatve

number , so Range : `f(t) >=0 or [0,oo)`

graph{3^(1/3)*sqrt(6x-2) [-20, 20, -10, 10]}