Question

If f(x) = 2x^2 - 4x +2, how would you find the equation of the tangent of the line of f(x) at the point (5,32) and the derivative when f'(5) = 16 ?

Answer 1

`y= 16x + 48`

Explanation:

Input the point `(5, 32)` into the equation of `y_2-y_1 = m(x_2-x_1)`.

The value of `m` being the value of 16.

`y - 32= 16 (x-5)`

`y = 16x - 80 +32`

`y= 16x -48`