Question

Question #c6afd

Answer 1

`4NH_3 + 5O_2 -> 4NO + 6H_2O`

Explanation:

`NH_3 + O_2 -> NO + H_2O`

Left Hand Side
1 x Nitrogen
3 x Hydrogen
2 x Oxygen

Right Hand Side
1 x Nitrogen
2 x Hydrogen
2 x Oxygen

I would approach this by considering multiplications of 3 and 2:
6, 12, 18....

`2NH_3 + O_2 -> 2NO + 3H_2O`

You can balance the hydrogen and nitrogen here, but not oxygen - you would need 2 1/2 `O_2`

`4NH_3 + 5O_2 -> 4NO + 6H_2O`

The equation is now completely balanced:

Left Hand Side
4 x Nitrogen
12 x Hydrogen
10 x Oxygen

Right Hand Side
4 x Nitrogen
12 x Hydrogen
10 x Oxygen