Question #09f05

1 Answer
Nov 11, 2017

#1/((sin2x)/x)# is the correct way

Explanation:

When you have #a/b# it is equivalent to writing #1/(b/a)#.

This is dividing the numerator and the denominator by the value of numerator.

So #\lim_(x\rightarrow 0) (2x)/(sin2x)=\lim_(x\rightarrow 0) 1/((sin2x)/(2x))#