Solve this system of equations: #4x-2y=6#, #3x+y=2#?

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Answer 1 · 2017-11-11T17:24:50

See below

Assuming second equation is #4x-2y=6#
Using substitution:

Isolate #y# in first equation:
#3x+y=2#
#y=2-3x#

Sub #y=2-3x# into second equation:
#4x-2(2-3x)=6#
#4x-4+6x=6#
#10x-4=6#
#10x=6+4#
#10x=10#
#x=1#

Sub #x=1# into first equation:
#3(1)+y=2#
#3+y=2#
#y=2-3#
#y=-1#
#:.POI=(1, -1)#

Alternatively, graph both lines to find the point of intersection.

Answer 2 · 2017-11-12T00:08:47

Here's the graph:

graph{(3x+y-2)(4x-2y-6)=0}