Solve this system of equations: #4x-2y=6#, #3x+y=2#?

2 Answers
Nov 11, 2017

See below

Explanation:

Assuming second equation is #4x-2y=6#
Using substitution:

Isolate #y# in first equation:
#3x+y=2#
#y=2-3x#

Sub #y=2-3x# into second equation:
#4x-2(2-3x)=6#
#4x-4+6x=6#
#10x-4=6#
#10x=6+4#
#10x=10#
#x=1#

Sub #x=1# into first equation:
#3(1)+y=2#
#3+y=2#
#y=2-3#
#y=-1#
#:.POI=(1, -1)#

Alternatively, graph both lines to find the point of intersection.

Here's the graph:

Explanation:

graph{(3x+y-2)(4x-2y-6)=0}