How do you graph #y = 5 -4x#?

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Answer 1 · 2017-11-12T18:38:30

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = 5 - (4 xx 0)#

#y = 5 - 0#

#y = 5# or #(0, 5)#

First Point: For #x = 2#

#y = 5 - (4 xx 2)#

#y = 5 - 8#

#y = -3# or #(2, -3)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-5)^2-0.05)((x-2)^2+(y+3)^2-0.05)=0 [-15, 15, -7.5, 7.5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y-5+4x)(x^2+(y-5)^2-0.05)((x-2)^2+(y+3)^2-0.05)=0 [-15, 15, -7.5, 7.5]}