Question #b68b4

1 Answer
kxoraxe
Nov 12, 2017

#y=-x+pi/2#

Explanation:

#f(x)=arccos x#
#f'(x)=-1/sqrt(1-x^2)#

#h=0#
#k=f(0)=arccos(0)=pi/2#

#m=f'(0)=-1/sqrt(1-(0)^2)#
#=-1/sqrt(1-0)#
#=-1/sqrt(1)#
#=-1/1#
#=-1#

#y-k=m(x-h)#
#y-pi/2=-1(x-0)#
#y=-x+0+pi/2#
#y=-x+pi/2#

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