How do you solve #\frac { x + 4} { x - 1} = x - 4#?

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Answer 1 · 2017-11-14T04:41:44

#=> x= 0 or x=6#

#\frac { x + 4} { x - 1} = x - 4#

By transposition:

# ( x + 4) = (x - 4) ( x - 1)#

#(x+4) = x^2 -4x-x+4#

#x+4 = x^2 -5x+4#

# x^2 -5x-x +4-4 = 0#

#=> x^2 -6x=0#

#=> x(x-6)=0#

#=> x= 0 or x-6=0#

#=> x= 0 or x=6#

The given expression is true for both the values of #x#.